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If I connect a large number of 40.0 μF capacitors in parallel across a 360.0 V...

If I connect a large number of 40.0 μF capacitors in parallel across a 360.0 V battery, how many capacitors do I need to store 207.4 J of energy?

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Answer #1

If all the capacitors are connected in parallel, then the potential difference across each capacitor will be 360V
The energy stored in each capacitor will be the same. i.e. E = (1/2)CV2

Energy stored in one capacitor, Eo=(1/2)*40*10-6*3602 = 2.592J

Number of capacitors needed to store 207.4J = 207.4/Eo

Number of capacitors needed to store required energy = 207.4/2.56 = 80

Therefore, 80 capacitors are needed to store the required energy

I hope i was able to answer your question. If you need anymore explanation, please ask in comments. I would be happy to help.

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