Question

A hammer is traveling 5.25 m/s when it strikes a nail It comes to a stop in 0.035 sec. If the hammer had a mass of 0.675 kg what was the average force that stopped the hammer?

Answer 1

Solution:

Using the concept of impulse is the change in momentum.

The hammer initially has a linear momentum of 0.675kg * 5.25 m/s = 3.54375 N-s.

Its final speed is 0 m/s, so its final momentum is 0 N-s.

The change in momentum = impulse = 3.54375 N*s.

The average force accompanying a change in momentum is given by the impulse divided by the time over which the impulse is delivered.

In this case, F = 3.54375 N*sec/0.035 sec = 101.25 N.

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