Question

9. Object #1 has mass m; object #2 has mass 10m. They are separated by the distance d. We can conclude that:

1. Object 1 exerts greater gravitational force on object 2, than object 2 exerts on 1.
2. Object 1 exerts smaller gravitational force on object 2, than object 2 exerts on 1.
3. Object 1 exerts on object 2 gravitational force equal in magnitude to force eqerted by 2 on 1.
4. Our answer depends on distance d.

10. Consider two objects: object 1 of mass m is positioned at origin of axis x; object 2 of mass 4m is positioned at x=+d. You want to place the third object of mass 2m on the axis x so that the net gravitational force acting on the third object from objects 1 and 2 will be equal 0.

1.1 Where on the axis x you should place the third object?

1. Somewhere at negative x.
2. Between x=0 and x=d
3. Somewhere at x positive and greater than d.
4. Answer depends on actual magnitude of masses and distance d.

1.2 You should place third object at:

1. x=d/4
2. x=d/3
3. x=d/2
4. x=2d/3
5. Answer depends on magnitudes of masses and distance.

1.3 Now the third object has mass 4m. What could you say about point of equilibrium now?

1. It will move closer to the object 1
2. It will move closer to the object 2
3. It will stay at the same position as in previous part of this question.
4. Impossible to predict.

1.4 What could you say about equilibrium in which the third object is?

1. Third object at point of zero force is in stable equilibrium.
2. Third object at point of zero force is in neutral equilibrium.
3. Third object at point of zero force is in unstable equilibrium.
4. Impossible to say anything about equilibrium.

Answer 1