Question

The pressure on the surface of a lake is Pat = 99.0 kPa.

(a) At what depth is the pressure 2P_at?

m

(b) If the pressure at the top of a deep pool of mercury is P_at, at what depth is the pressure 2P_at?

cm

Answer 1

Solution:-

Given

Pat = 99.0 kpa

a)      Calculate at what depth is the pressure 2 pat?

Density of water = 1000 kg/m³

Density of mercury = 13645 kg/m³

Pressure at depth, h = pressure at top + hdg

2p – at = p at + hdg

P - at = hdg

h = p – at / (dg)

= (99.0)*10³ / (10³ * 9.8)

= 10.10 m

b)     Calculate depth is the pressure 2 pat

      2p – at = p at + hdg

h = p – at / (dg)

= (99.0)*10³ / (13.645 *10³ * 9.8)

= 0.7403 m

= 74.03 cm