Question

Two loudspeakers emit 500 Hz sound waves with an amplitude of
1cm.

Speaker 2 is 1.00m behind speaker 1, and the phase difference
between the

speakers is 90 degree

. (I) What is the phase difference of the sound wave at a

point 2.00 m in front of speaker 1? (II) What is the minimum
distance

between the two speakers such that the observer at this position
hears

the minimal sound? (6 points)

Answer #1

Some assumptions made are:

i) S2 leads S1 by a phase difference of 90o.

ii) Speed of sound in air = 340 m/s

Making these assumptions, all calculations are done. If you still have any doubts, kindly mention in comments.

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