Question

A 0.50-μF and a 1.4-μF capacitor (C₁ and C₂, respectively) are connected in series to a 14-V battery.

a) Calculate the potential difference across each capacitor.

Express your answers using two significant figures separated by a comma.

V₁ V₂ =

b) Calculate the charge on each capacitor.

Express your answers using two significant figures separated by a comma.

Q₁ Q₂ =

c) Calculate the potential difference across each capacitor assuming the two capacitors are in parallel.

Express your answers using two significant figures separated by a comma.

V₁ V₂ =

d)Calculate the charge on each capacitor assuming the two capacitors are in parallel.

Express your answers using two significant figures separated by a comma.

Q₁ Q₂ =

Answer 1

In series combination equivalent capacitance is

C= C1×C2/ C1+ C2

= 0.50 ×1.40/ ( 0.50 + 1.40) F

= 0.37 F

Now charge on each capacitor is

Q = CV

= 0.37× 14  C

= 5. 18 C

a) V1 = Q/C1

= 5.18/ 0.50 V

= 10.36 V

V2 = Q/C2

= 5.18/ 1.4 V

= 3. 7 V

b. Q1= Q2 = Q =5.18 C

C. In parallel combination

V1= V2 = 14V

d. Q1= C1V1

= 0.50 ×14  C

= 7.0   C

Q2 = C2V2

= 1.4 × 14  C

= 19.6 C