Two ice skaters, with masses of 30.0 kgkg and 75.0 kgkg , are at the center of a 60.0 mm -diameter circular rink. The skaters push off against each other and glide to opposite edges of the rink.
If the heavier skater reaches the edge in 40.0 ss , how long does the lighter skater take to reach the edge?
Let
m1 = 75 kg
m2 = 30 kg
The final momentum must be zero as they come to rest
so,
m1v1f + m2v2f = 0
m1v1f = - m2v2f
v1f / v2f = - m2 / m1
v1f / v2f = - 30 / 75
v1f / v2f = - 0.4 ---- (1)
let x be the distance traveled by each skaet.
If heavier skater travles 'x' then lighter skater travels '-x'
so,
x = 40 * v1f
and
-x = t2 * v2f
the distance is same
x = -x
40 * v1f = - t2 * v2f
v1f = - t2 * v2f / 40 ------ (2)
using (1) and (2)
- 0.4 * v2f = - t2 * v2f / 40
0.4 = t2 / 40
t2 = 16 seconds
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