Question

A real, upright object of 3.50 cm in height is placed to the left of a...

A real, upright object of 3.50 cm in height is placed to the left of a converging lens with focal length 12.0 cm. A diverging lens with focal length 6.00 cm is located 20.0 cm to the right of the converging lens.

Read carefully: The final image formed by the two lens system is 5.00 cm to the right of the converging lens.

  1. Draw a simple yet clear diagram of the setup, labeling lenses, object distances, and images distances as appropriate as you work through parts (b), (c), and (d).
  2. Determine the position of the original object (with respect to the converging lens).
  3. Is the final image inverted or upright relative to the original object?

Is the final image real or virtual?

Science   Physics   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A 1.8 cm tall object is placed 5 cm to the left of a converging lens...
A 1.8 cm tall object is placed 5 cm to the left of a converging lens (lens #1) with a focal length of 1.3 cm. To the right of this converging lens is a diverging lens (lens #2) that has a focal length of 2.6 cm. The diverging lens is placed 22.4 cm from the converging lens. Where is the final image, is it real or virtual, and is it upright or inverted?
An object is placed 5cm in front of a diverging lens of focal length 25 cm....
An object is placed 5cm in front of a diverging lens of focal length 25 cm. A second converging lens of focal length 15cm is positioned 20 cm to the right of the first lens. What is the final image distance? What is the magnification of the final image? Is it upright of inverted? Real or virtual?
An object which is 1.23 cm high is placed 10.00 cm to the left of a...
An object which is 1.23 cm high is placed 10.00 cm to the left of a lens. It is not known if the lens is converging or diverging. An image forms 3.20 cm to the left of the lens. (a) Determine if the lens is converging or diverging by calculating the focal length of the lens. (b) Calculate the height of the image. (c) Describe the image. Is it real or virtual, upright or inverted and enlarged or diminished?
An object which is 1.23 cm high is placed 10.00 cm to the left of a...
An object which is 1.23 cm high is placed 10.00 cm to the left of a lens. It is not known if the lens is converging or diverging. An image forms 3.20 cm to the left of the lens. (a) Determine if the lens is converging or diverging by calculating the focal length of the lens. (3) (b) Calculate the height of the image. (1) (c) Describe the image. Is it real or virtual, upright or inverted and enlarged or...
A diverging lens with a focal length of -19.7 cm and a converging lens with a...
A diverging lens with a focal length of -19.7 cm and a converging lens with a focal length of 11.0 cm have a common central axis. Their separation is 39.5 cm. An object of height 1.1 cm is 26.4 cm in front of the diverging lens, on the common central axis. Find the location of the final image produced by the combination of the two lenses. Where is the image located as measured from the converging lens? What is the...
An object of height 6.00 cm is placed 24.0 cm to the left of a converging...
An object of height 6.00 cm is placed 24.0 cm to the left of a converging lens with a focal length of 10.5 cm. Determine the image location in cm, the magnification, and the image height in cm. (a) the image location in cm (b) the magnification (c) the image height in cm (d) Is the image real or virtual? (e) Is the image upright or inverted?
A converging lens with a focal length of 4.8 cm is located 24.8 cm to the...
A converging lens with a focal length of 4.8 cm is located 24.8 cm to the left of a diverging lens having a focal length of -15.0 cm. If an object is located 9.8 cm to the left of the converging lens, locate and describe completely the final image formed by the diverging lens. Where is the image located as measured from the diverging lens? What is the magnification? Also determine, with respect to the original object whether the image...
An 9.0 cm toy rocket is placed 15 cm to the left of a converging lens...
An 9.0 cm toy rocket is placed 15 cm to the left of a converging lens having a focal length of 6.0 cm. A second lens is located 36 cm to the right of the first lens (see Figure). The final image formed by the two lenses is located 13 cm to the left of the second lens. (a) What is the focal length of the second lens? Is it converging or diverging? (b) How tall is the final image?...
An object is 17.4 cm to the left of a lens with a focal length of...
An object is 17.4 cm to the left of a lens with a focal length of 12.4 cm. A second lens of focal length 14.7 cm is 54.91 cm to the right of the first lens. The height of the object of is 3.6 cm. What is the location of the final image with respect to the second lens? What is the height of the image? Also determine is the image real or virtual and, with respect to the original...
Two converging lenses (f1 = 9.00 cm and f2 = 6.00 cm) are separated by 18.0...
Two converging lenses (f1 = 9.00 cm and f2 = 6.00 cm) are separated by 18.0 cm. The lens on the left has the longer focal length. An object stands 10.0 cm to the left of the left-hand lens in the combination. (a) Locate the final image relative to the lens on the right. (b) Obtain the overall magnification. (c) Is the final image real or virtual? With respect to the original object, (d) is the final image upright or...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT