Question

Two charges of 1.0 microcoulomb and -2.5 microcoulomb respectively are held in place 4 millimeters apart. A third charge of 1.7 microcoulomb is somewhere on the same line as two charges but it experiences no force. Determine the location of the 1.7 microcoulomb relative to the 1.0 microcoulomb charge. A.) Write the analytic for the force on the 1.7microcoulomb. B.) State explicitly which concept is involved C.) Solve the equation in A and state the solution

Answer 1

we know that simlar charge repel each other and diffrent in sign are attract each other

there are two charge at corner 1.0C and -2.5C so if we palced a third in some where between than -ve charge attract and positive charge repel it so it is clear that it feel force because direction of force by both are same and it attract toward negative so it is clear it will not in betwwen of them

so it will either side of both now task is which side we placed so anyltically we know that

F is proportioanl to charge and iversally proportionally to square of distance

so if we palced it -ve charge side distnace is less and charge is already higher thn +ve so it will be palced near to +ve side

where K= 9.0 x 10⁹ N. m² / C².

let distance is d from positive charge

F(by negative charge)=F(by positve charge)

so now it become

we already decide the direction so we did not consider -ve sign of charge it only given for directio

2.5d² =( 4*10^-3+d)²

taking root of both side

1.58114d=4*10^-3 + d

d=6.883*10^-3meter

d=6.883 mm from p0sive charge