Question

A golfer putts the ball on the green toward the right (positive x direction). if the coefficient of rolling friction is 0.045, find the balls acceleration in m/s^2 (the sign of acceperation matters)

Answer 1

SOLUTION::

A golfer putts the ball on the green toward the right (positive x direction).

Then the coefficient of rolling friction is   =0.045

we know the the balls acceleration  

......................................(1)

there ball toward the right or positive side so acceleration also oppsite side so negative sign

where a= the balls acceleration

g = 9.8 m/s2

put the all values on equation (1)

   The balls acceleration Of ball = -0.44 m/s2

ANSWER = -0.44 m/s2