de Broglie wavelength of a 1.4 keV electron?
Answer: The de broglie wavelength of a particle of mass m is given by
Where p is the momentum of the particle.
Also the relation between the kinetic energy and momentum of a particle is given by
Therefore the de broglie wavelength of the electron becomes
Substituting the given value of energy
E = 1.4 KeV = 1.4 * 10^(3) eV
As 1eV = 1.6 × 10^(-19) joules
Therefore, E = 1.4 * 10^(3) * 1.6 * 10^(-19) joules
and mass of electron, m = 9.11 *10^(-31) kg
and planks constant, h = 6.626 * 10^(-34) js
Which is the required de-broglie wavelength of the electron
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