Question

de Broglie wavelength of a 1.4 keV electron?

___ nm

Answer #1

Answer: The de broglie wavelength of a particle of mass m is given by

Where p is the momentum of the particle.

Also the relation between the kinetic energy and momentum of a particle is given by

Therefore the de broglie wavelength of the electron becomes

Substituting the given value of energy

E = 1.4 KeV = 1.4 * 10^(3) eV

As 1eV = 1.6 × 10^(-19) joules

Therefore, E = 1.4 * 10^(3) * 1.6 * 10^(-19) joules

and mass of electron, m = 9.11 *10^(-31) kg

and planks constant, h = 6.626 * 10^(-34) js

We get,

Or

Which is the required de-broglie wavelength of the electron

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If the De Broglie wavelength of an electron is equal to 450
nm calculate the velocity of the electron. Assume that the
electron's speed is non-relativistic.
Tries 0/10
If the kinetic energy of an electron is 170 eV,
calculate its De Broglie wavelength. For this non-relativistic
electron you must first calculate its velocity from the general
kinetic energy equation. Then you can find the De Broglie
wavelength of the electron.

Calculate the de Broglie wavelength of (a) a
0.613 keV electron (mass = 9.109 × 10-31 kg),
(b) a 0.613 keV photon, and (c) a
0.613 keV neutron (mass = 1.675 × 10-27 kg).

Find the speed of the following objects given their de Broglie
wavelength:
a. An electron with a wavelength of 0.2 nm
b. A proton with a wavelength of 0.2 nm
c. A 200 g baseball with a wavelength of 0.2 nm (in m/s and
mi/hr)
d. Explain the differences.

What is the de Broglie wavelength of an electron (m = 9.11 ×
10^–31 kg) in a 5.0 × 10^3-volt X-ray tube?
a. 0.017 nm
b. 0.007 nm
c. 0.028 nm
d. 0.034 nm
e. 0.014 nm

PART A: What is the de Broglie wavelength of an electron
accelerated through 750 V ? Express your answer in nanometers.
PART B: What is the de Broglie wavelength of a proton
accelerated through the same potential difference?
Express your answer in nanometers.

Find the de Broglie wavelength of an electron with a speed of
0.95c. Take relativistic effects into account.

A photon has a wavelength that is the same as the de Broglie
wavelength of an electron.
(a) How does the momentum of the photon, compare to the momentum of
the electron,
(b)How does the energy of the photon, compare to the total
energy of the electron

What is the kinetic energy in eV of an electron whose de Broglie
wavelength is 18 % of the wavelength of a photon having the energy
equal to electrons kinetic energy?
Answer in eV

Calculate the linear momentum, and the de Broglie wavelength
of:
a) a 0.75 kg bullet that is fired at a speed of 100 m /
s,
b) a non-relativistic electron with a kinetic energy of 2.0
eV, and
c) a relativistic electron with a kinetic energy of 208
keV.
!!!! # !! Remember that for relativistic particles: ? = ? ? +
? "? and ? = ?? = ? + ?" ?, the mass
of the electron is 9.11...

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