Question

de Broglie wavelength of a 1.4 keV electron?

___ nm

Answer #1

Answer: The de broglie wavelength of a particle of mass m is given by

Where p is the momentum of the particle.

Also the relation between the kinetic energy and momentum of a particle is given by

Therefore the de broglie wavelength of the electron becomes

Substituting the given value of energy

E = 1.4 KeV = 1.4 * 10^(3) eV

As 1eV = 1.6 × 10^(-19) joules

Therefore, E = 1.4 * 10^(3) * 1.6 * 10^(-19) joules

and mass of electron, m = 9.11 *10^(-31) kg

and planks constant, h = 6.626 * 10^(-34) js

We get,

Or

Which is the required de-broglie wavelength of the electron

If the de Broglie wavelength of an electron is 258 nm , what is
the kinetic energy of this electron?

If the De Broglie wavelength of an electron is equal to 450
nm calculate the velocity of the electron. Assume that the
electron's speed is non-relativistic.
Tries 0/10
If the kinetic energy of an electron is 170 eV,
calculate its De Broglie wavelength. For this non-relativistic
electron you must first calculate its velocity from the general
kinetic energy equation. Then you can find the De Broglie
wavelength of the electron.

Calculate the de Broglie wavelength of (a) a
0.613 keV electron (mass = 9.109 × 10-31 kg),
(b) a 0.613 keV photon, and (c) a
0.613 keV neutron (mass = 1.675 × 10-27 kg).

Calculate the de Broglie wavelength of
(a) a 0.942 keV electron (mass = 9.109 ×
10-31 kg),
(b) a 0.942 keV photon, and
(c) a 0.942 keV neutron (mass = 1.675 ×
10-27 kg).

Calculate the de Broglie wavelength of (a) a
1.59 keV electron (mass = 9.109 × 10-31 kg),
(b) a 1.59 keV photon, and (c) a
1.59 keV neutron (mass = 1.675 × 10-27 kg).

An electron has a de Broglie wavelength of 215 nm, what is the
speed of the electron?

Find the speed of the following objects given their de Broglie
wavelength:
a. An electron with a wavelength of 0.2 nm
b. A proton with a wavelength of 0.2 nm
c. A 200 g baseball with a wavelength of 0.2 nm (in m/s and
mi/hr)
d. Explain the differences.

What is the de Broglie wavelength of an electron (m = 9.11 ×
10^–31 kg) in a 5.0 × 10^3-volt X-ray tube?
a. 0.017 nm
b. 0.007 nm
c. 0.028 nm
d. 0.034 nm
e. 0.014 nm

1. a) What is the de Broglie wavelength of an electron that is
accelerated through an electrical potential difference of 20 volts?
b) What is the de Broglie wavelength of a proton that is
accelerated through an electrical potential difference of 20
volts?

1) How will the wavelength of de Broglie electron change if you
increase it
speed 3 times?
2) How much is the wavelength of de Broglie proton different from
the wavelength
where is the Broglie electron if they move at the same speed?
3) Will the wavelength of the particle change if it enters the
potential field?

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