Question

A cube of ice is taken from the freezer at -9.5 ?Cand placed in a 95-g aluminum calorimeter filled with 330 g of water at room temperature of 20.0 ?C. The final situation is observed to be all water at 17.0 ?C. The specific heat of ice is 2100 J/kg?C?, the specific heat of aluminum is 900 J/kg?C?, the specific heat of water is is 4186 J/kg?C?, the heat of fusion of water is 333 kJ/Kg.

What was the mass of the ice cube?

Answer #1

let mass of the ice cube be m kg.

then heat lost by aluminum + heat lost by water=heat gained by ice

==>mass of aluminum *specific heat of aluminum*decrease in temperature +mass of water*specific heat of water*decrease in temperature=mass of ice *specific heat of ice*temperature increase from -9.5 to 0 degree + mass of ice*latent heat of fusion+mass of melted water*specific heat of water*temperature change from 0 to 17 degrees

==>0.095*900*(20-17)+0.33*4186*(20-17)=m*2100*(0-(-9.5))+m*333*10^3+m*4186*(17-0)

==>4400.6=424112*m

==>m=0.010376 kg

=10.376 grams

A cube of ice is taken from the freezer at -9.5 ∘C and placed in
a 95-g aluminum calorimeter filled with 320 g of water at room
temperature of 20.0 ∘C. The final situation is observed to be all
water at 15.0 ∘C. The specific heat of ice is 2100 J/kg⋅C∘, the
specific heat of aluminum is 900 J/kg⋅C∘, the specific heat of
water is is 4186 J/kg⋅C∘, the heat of fusion of water is 333
kJ/Kg.
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specific heat of aluminum is 900 J/kg?C?, the specific heat of
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A cube of ice is taken from the freezer at -8.5 ∘C and placed in
a 85-g aluminum calorimeter filled with 320 g of water at room
temperature of 20.0 ∘C. The final situation is observed to be all
water at 15.0 ∘C. The specific heat of ice is 2100 J/kg⋅C∘, the
specific heat of aluminum is 900 J/kg⋅C∘, the specific heat of
water is is 4186 J/kg⋅C∘, the heat of fusion of water is 333
kJ/Kg.

A cube of ice is taken from the freezer at -6.5 ∘C and placed in
a 95-g aluminum calorimeter filled with 300 g of water at room
temperature of 20.0 ∘C. The final situation is observed to be all
water at 16.0 ∘C. The specific heat of ice is 2100 J/kg⋅C∘, the
specific heat of aluminum is 900 J/kg⋅C∘, the specific heat of
water is is 4186 J/kg⋅C∘, the heat of fusion of water is 333
kJ/Kg.
Part A What...

A cube of ice is taken from the freezer at -8.5 ∘C and placed in
a 85-g aluminum calorimeter filled with 320 g of water at room
temperature of 20.0 ∘C. The final situation is observed to be all
water at 15.0 ∘C. The specific heat of ice is 2100 J/kg⋅C∘, the
specific heat of aluminum is 900 J/kg⋅C∘, the specific heat of
water is is 4186 J/kg⋅C∘, the heat of fusion of water is 333 kJ/Kg.
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A cube of ice is taken from the freezer at -8.50 oC and placed
in an 85 g aluminum calorimeter filled with 310 g of water at room
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Chapter 18, Problem 041
(a) Two 58 g ice cubes are dropped into 410 g
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