Question

1. What is the impulse? Give the definition and
formula.

2. Calculate the impulse required to stop each moving
ball described below.

m_{A} = 4.55 kgv_{A} = 1.5 m/sm_{B} = 0.7
kgv_{B} = 9 m/sm_{C} = 1.05 kgv_{C} = 4.5
m/sm_{D} = 0.84 kgv_{D} = 6.75 m/s

The impulse for ball 'A', Imp_{A} = Units Select
an answer kg m s m/s N*s N/s no units required .

The impulse for ball 'B', Imp_{B} = Units Select
an answer s kg N*s m N/s m/s no units required .

The impulse for ball 'C', Imp_{C} = Units Select
an answer N/s m s kg N*s m/s no units required .

The impulse for ball 'D', Imp_{D} = Units Select
an answer m kg N*s m/s N/s s no units required .

3. Rank these balls from the hardest to easiest to stop.

D,C,A,B

A,B,D,C

A,B,C,D

C,D,B,A

B,D,A,C

B,C,D,A

Answer #1

**1.**Impulse J of the force F during a given time
is defined as the force multiplied by its applied time.

**J = Ft**

According to the impulse momentum theorem,Impulse on an object is equal to the change in momentum of the object.

**2.**Let J_{A}, J_{B,}
J_{C} and J_{D} are impulse required to stop the
ball A,B,C and D respectively.

J_{A} = m_{A} v_{A} = 4.55*1.5 = 6.825
unit

J_{B} = m_{B} v_{B} = 0.7*9 = 6.3
unit

J_{C} = m_{C} v_{C} = 1.05*4.5 = 4.725
unit

J_{D} = m_{D} v_{D} = 0.84*6.75 = 5.67
unit

**3.**For more value of impulse,more difficult to
stop the ball is. So, rank from hardest to easiest is
**ABDC**

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