Question

1. What is the impulse? Give the definition and formula.

2. Calculate the impulse required to stop each moving ball described below.
m_A = 4.55 kgv_A = 1.5 m/sm_B = 0.7 kgv_B = 9 m/sm_C = 1.05 kgv_C = 4.5 m/sm_D = 0.84 kgv_D = 6.75 m/s
The impulse for ball 'A', Imp_A =  Units Select an answer kg m s m/s N*s N/s no units required  .
The impulse for ball 'B', Imp_B =  Units Select an answer s kg N*s m N/s m/s no units required  .
The impulse for ball 'C', Imp_C =  Units Select an answer N/s m s kg N*s m/s no units required  .
The impulse for ball 'D', Imp_D =  Units Select an answer m kg N*s m/s N/s s no units required  .
3. Rank these balls from the hardest to easiest to stop.

D,C,A,B

A,B,D,C

A,B,C,D

C,D,B,A

B,D,A,C

B,C,D,A

Answer 1

1.Impulse J of the force F during a given time is defined as the force multiplied by its applied time.

J = Ft

According to the impulse momentum theorem,Impulse on an object is equal to the change in momentum of the object.

2.Let J_A, J_B, J_C and J_D are impulse required to stop the ball A,B,C and D respectively.

J_A = m_A v_A = 4.55*1.5 = 6.825 unit

J_B = m_B v_B = 0.7*9 = 6.3 unit

J_C = m_C v_C = 1.05*4.5 = 4.725 unit

J_D = m_D v_D = 0.84*6.75 = 5.67 unit

3.For more value of impulse,more difficult to stop the ball is. So, rank from hardest to easiest is ABDC