Question

A copper rod has a length of 4 meters, and its sectional area it is 5...

A copper rod has a length of 4 meters, and its sectional area it is 5 x 10^-4 m^2. Heat enters through the left end of the rod and exits through the
rightmost. Copper has a thermal conductivity of 386 W / m ° C. If the heat flux through the rod is 2400 W, determine the difference in temperatures at the two ends.
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Answer #1

Heat flux= (T) / [1/k *L/A], where T is temperature difference, k is thermal conductivity, L is length and A is cross sectional area.

So,T=(heat flux)*[1/k *L/A]

For the given problem, heat flux=2400 W, k= 386 W/mC, L= 4 meters and A=5*10^-4 m2.

So, T=2400*[1/386 * 4/(5*10^-4)] = 49740.9 degrees celsius.

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