Question

A single slit, 2000 nm wide, forms a diffraction pattern when illuminated by monochromatic light of 520-nm wavelength. A. What is the largest angle from the central maximum at which the intensity of the light is zero? B. Find the angle at which the fourth minimum of the pattern occurs away from the central maximum

Answer 1

Solution :

Given :

d = 2000 nm = 2000 x 10^-9 m

= 520 nm = 520 x 10^-9 m

.

According to Bragg's Equation :

For largest angle : = 90^o

Thus : n = d / = (2000 x 10^-9 m) / (520 x 10^-9 m) = 3.846 3

.

Therefore, The largest angle will be given as :

(3)(520 x 10^-9 m) / (2000 x 10^-9 m) = 0.78

.

Therefore: Largest angle from the central maximum at which the intensity is zero will be 51.26^o.