A 5.00 μC charge is moving at a constant speed of 6.90×10^{5} m/s in the +x−direction relative to a reference frame. At the instant when the point charge is at the origin, what is the magneticfield vector it produces at the following points. 
Part A x=0.500m,y=0, z=0 Enter your answers numerically separated by commas.
SubmitRequest Answer Part B x=0, y=0.500m, z=0 Enter your answers numerically separated by commas.
SubmitRequest Answer Part C x=0.500m, y=0.500m, z=0 Enter your answers numerically separated by commas.
SubmitRequest Answer Part D x=0, y=0, z=0.500m Enter your answers numerically separated by commas.

i,j and k are unit vector towards x, y, and xdirection.
Magnetic filed due to moving charge,
v = (6.9E5î + 0ĵ + 0k̂) m/s
r = (0.5î + 0ĵ + 0k̂) m
r² = (0.5² + 0² + 0²) = 0.25
r = 0.5
we know that cross product of two vectors in the same direction is 0. So,
so, B=0 and Bx=0, By=0 and Bz=0
part(B)
r = (0î + 0.5ĵ + 0k̂) m
r² = (0 + 0.5² + 0²) = 0.25
r = 0.5
So, magnetic field
Bx=0, By=0 and
part(C)
r = (0.5î + 0.5ĵ + 0k̂) m
r² = ( 0.5²+ 0.5² + 0²) = 0.5
r =
so,
So, it has only component in z direction, Bx=0, By=0 and
part(d)
r = (0î + 0ĵ + 0.5k̂) m
r² = ( 0²+ 0² + 0.5²) = 0.25
r =0.5
So, Bx=0 and Bz=0 ,
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