Question

A straight, 2.50 mm wire carries a typical household current of 1.50 AA (in one direction) at a location where the earth's magnetic field is 0.550 gauss from south to north.

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Part A

Part complete

Find the direction of the force that our planet's magnetic field exerts on this wire if is oriented so that the current in it is running from west to east.

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The force is directed upward.

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Correct

Part B

Part complete

Find the magnitude of the force that our planet's magnetic field exerts on this wire if is oriented so that the current in it is running from west to east.

Express your answer with the appropriate units.

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Part C

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Find the direction of the force if the current in this wire is running vertically upward.

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Please ChooseThe force is directed from east to west. The force is directed from west to east. The force is directed from north to south. The force is directed from south to north.

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Part D

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Find the magnitude of the force if the current in this wire is running vertically upward.

Express your answer with the appropriate units.

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F1F1 =

nothing nothing

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Part E

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Find the direction of the force if the current in this wire is running from north to south.

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Please ChooseThe force is directed upward. The force is directed downward. There is no force exerting on the wire. The force is directed from north to south.

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Part F

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Find the magnitude of the force if the current in this wire is running from north to south.

Express your answer with the appropriate units.

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F2F2 =

nothing nothing

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Part G

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Is the magnetic force ever large enough to cause significant effects under normal household conditions?

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Please ChooseYes No

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F3F3 =

nothing nothing

Answer 1

A)

Using right hand rule, the direction of magnetic force on the wire comes out to be in upward direction.

B)

i = current in the wire = 1.50 A

L = length = 2.50 mm = 2.50 x 10-3 m

B = magnetic field = 0.55 G = 0.55 x10-4 T

magnitude of magnetic force is given as

F = i B L

F = (1.50)(0.55 x10-4)(2.50 x 10-3)

F = 2.0625 x 10-7 N

C)

Using right hand rule , the direction of the magnetic field comes out to be towards West.

D)

i = current in the wire = 1.50 A

L = length = 2.50 mm = 2.50 x 10-3 m

B = magnetic field = 0.55 G = 0.55 x10-4 T

magnitude of magnetic force is given as

F = i B L

F = (1.50)(0.55 x10-4)(2.50 x 10-3)

F = 2.0625 x 10-7 N

E)

There will be no force on the wire since current is parallel to the direction of magnetic field.

F)

F = 0 N