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A car stating from rest accelerates at 2 m/s2 for 5 seconds. The driver then maintians...

A car stating from rest accelerates at 2 m/s2 for 5 seconds. The driver then maintians a steady speed for 12 seoncds. The car the undergoes an accelration of -2.5m/s2 until it reaches a speed of 4 m/s. A. what was the speed of the car after 2 seconds? B. how far did the car travel during the interval of constant speed? C. how much time did the car spend slowing down? d. what was the total distane the car traveled?

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Homework Answers

Answer #1

a)

v = at =2*2 = 4 m/s

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b)

Final velocity after 5 seconds

v = 2*5= 10m/s

Distance travelled = v*t = 10*12 = 120 m

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c)using 1st equation of motion

t = (10-4)/2.5

t = 2.4 seconds

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d) distance travelled during Acceleration

d1 = 0.5* 2* 5*5 = 25m

Distance during constant speed

d2 = 120 m

Distance travlled during deceleration

d3 = (100 - 16)/(2* 2.5)

d3 = 16.8 m

Net distance = d1 + d2 + d3 = 161.8 m

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Comment in case any doubt.. Goodluck

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