Question

Two dragonflies have the following equations of motion: x1 = 2.2 m + (0.71 m/s )t...

Two dragonflies have the following equations of motion:

x1 = 2.2 m + (0.71 m/s )t

x2 = –3.1 m + (1.4 m/s )t

Which dragonfly is moving faster?​

Which dragonfly starts out closer to x = 0 at t = 0?

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Homework Answers

Answer #1

Answer:

a) So dragonfly with equation x2 = -3.1 m + (1.4m/s)t has more speed.

b) At t = 0, dragonfly with equation x1 = 2.2 m + (0.71m/s)t starts out closer to x = 0.

Explanation:

The equations of motions of 2 dragonflies are given by   

x1 = 2.2 m + (0.71 m/s )t

x2 = –3.1 m + (1.4 m/s )t

a) The velocity of a body is given by the expression

  

So dragonfly with x2 = -3.1 m + ( 1.4 m/s ) t is moving faster.

b) At t = 0

x1 = 2.2 m + (0.71 m/s) * 0 = 2.2m

x2 = -3.1 m + ( 1.4 m/s) * 0 = -3.1m

So at t = 0 dragonfly following equation x1 = 2.2m + (0.71 m/s)t starts out closer to x = 0.

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