Two dragonflies have the following equations of motion:
x1 = 2.2 m + (0.71 m/s )t
x2 = –3.1 m + (1.4 m/s )t
Which dragonfly is moving faster?
Which dragonfly starts out closer to x = 0 at t = 0?
Answer:
a) So dragonfly with equation x2 = -3.1 m + (1.4m/s)t has more speed.
b) At t = 0, dragonfly with equation x1 = 2.2 m + (0.71m/s)t starts out closer to x = 0.
Explanation:
The equations of motions of 2 dragonflies are given by
x1 = 2.2 m + (0.71 m/s )t
x2 = –3.1 m + (1.4 m/s )t
a) The velocity of a body is given by the expression
So dragonfly with x2 = -3.1 m + ( 1.4 m/s ) t is moving faster.
b) At t = 0
x1 = 2.2 m + (0.71 m/s) * 0 = 2.2m
x2 = -3.1 m + ( 1.4 m/s) * 0 = -3.1m
So at t = 0 dragonfly following equation x1 = 2.2m + (0.71 m/s)t starts out closer to x = 0.
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