Question

Calculate the final velocity right after a 119 kg rugby player who is initially running at 7.45 m/s collides head‑on with a padded goalpost and experiences a backward force of 18500 N for 5.50×10−2 s

Answer #1

Mass of the rugby player = m = 119 kg

Initial velocity of the player = V_{1} = 7.45 m/s

Final velocity of the player = V_{2}

Backwards force on the player = F = -18500 N

Negative as the force is acting in the direction opposite to the initial velocity of the player.

Time period = T = 5.5 x 10^{-2} sec

The impulse of the force is equal to the change in momentum of the player.

FT = mV_{2} - mV_{1}

FT = m(V_{2} - V_{1})

(-18500)(5.5x10^{-2}) = (119)(V_{2} - 7.45)

-8.55 = V_{2} - 7.45

V_{2} = -1.1 m/s

Negative sign indicates the velocity of the player is in the opposite direction of the initial velocity of the player.

Final velocity of the player = -1.1 m/s

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