Question

A level road makes a 90 degree turn with a 73m radius of a curvature. What is the maximum speed for a car to negotiate this turn.

a) When the road is dry and the coefficient of static friction is .88

Answer 1

When a car take a turn of 90 degrre ,it moves in circular motion.and maximum speed allow in circular motion is √urg.

Where u=friction coefficient.R=radius of curvature,g=acceleration due to gravity,

V=√.88×73×9.8=√629.522=25.09m/s

Note:-√ this symbol means square root.

For circular motion it is not necessary that car moves in complete circle,if car moves on in circular arc then also it is consider as circular motion.

If u have any doubt then feel free to ask.