Question

An NTC thermistor with a resistance of 10 kΩ at 25°C has a. B = 3799...

An NTC thermistor with a resistance of 10 kΩ at 25°C has a. B = 3799 K for the B model.
b.   a=2.1085×10−3,   b=7.9792×10−5 and   c=6.5351×10−7 for the SH model. When in contact with an object, the thermistor has a resistance of 5 kΩ. Calculate and compare the temperatures predicted by the two calibration models.

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Answer #1

(a) B(T1/T2) = (T2 * T1) / (T2 - T1) * ln(R1 / R2)

T2 = 25 + 273 K = 298 K , R2 = 10k , R1 = 5k , B=3799K

3799 = (298*T1)/ (298 - T1) * ln(1/2)

3799 / -0.693 =  (298*T1)/ (298 - T1)

-5482(298-T1) = 298*T1

1633636= 5184T1

T1 = 315.13 K (approx) = 42c.

(B) 1 / T = A + B ln(R) + C ln(R)3 = 2.1085* 10-3 + 7.9792*10-5 ln(5000) + 6.5351*10-7 ln(5000)3 = 0.0021 + 8.517*7.9792/100000 + 6.5351*(8.517)3/10000000

1/T = 0.0021 + 0.000679 + 0.0004037 = 0.0031827

T = 314.19 K

T = 41c.

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