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A particle moves in the xy plane. Its position vector function of time is ?⃑ =...

A particle moves in the xy plane. Its position vector function of time is ?⃑ = (2?3 − 5?)?̂ + (6 − 7?4)?̂ where r is in meters and t is in seconds.

a) In unit vector notation calculate the position vector at t =2 s.
b) Find the magnitude and direction of the position vector for part a.
c) In unit vector notation calculate the velocity vector at t =2 s.
d) Find the magnitude and direction of the velocity vector for part b.
e) In unit vector notation calculate the acceleration vector at t =2 s.
f) Find the magnitude and direction of the acceleration vector for part e.

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Homework Answers

Answer #1

Given ?⃑ = (2?3 − 5?)?̂ + (6 − 7?4)?̂

a) Position Vector at t=2s

b) Magnitude:

Direction :

c)

d) Magnitude =

Direction =

e) Similarly Accleration =

f) Magnitude =

Direction =

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