The top half of the ring with radius R is "+ Q", the
bottom half is "-Q". On its axis, the charged particle "Q", 10R
from the center, has the speed "Vo". What will be its speed when
the particle comes to 3R?
Q=5,0 C
R=6,0 cm
k=9×10^9 N×m^2/C^2
q=2,0 C
m= 2,0×10^16 kg
V0= 5,0×10^4 m/s
Dear student,
Find this solution, and RATE IT ,If you find it is helpful .your rating is very important to me.If any incorrectness ,kindly let me know I will rectify them soon.
Thanks for asking ..
Get Answers For Free
Most questions answered within 1 hours.