Question

A spherical shell of radius 3.84 cm and a cylinder of radius 7.22 cm are rolling...

A spherical shell of radius 3.84 cm and a cylinder of radius 7.22 cm are rolling without slipping along the same floor. The two objects have the same mass. If they are to have the same total kinetic energy, what should the ratio of the spherical shell's angular speed to the cylinder's angular speed be?

Homework Answers

Answer #1

Rshell = 3.84 cm

= 0.0384 m

Rcylinder = 7.22 cm

= 0.0722 m

first the moment of inertia of the shell is = 2/3 M R2

and speed is 1 = v1 / r1

total KEshell = 1/2 m v2 + 1/2 I2

= 5/6 mv2

sameway

total KEcylinder = 3/4 mv2

now if KEshell and KEcylinder are same then

Vshell / Vcylinder = ( 9/10 )1/2

so

shell Rshell /cylinder Rcylinder = ( 9/10 )1/2

shell / cylinder= ( 9/10 )1/2 ( Rcylinder / Rshell )

= ( 9/10 )1/2 ( 0.0722/ 0.0384 )

shell / cylinder= 1.7837222

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