In a TV tube an electric potential difference accelerates electrons from a rest position towards a screen. Just before reaching the screen, the electrons have a wavelength of 1.2×10^−11?. Determine the kinetic energy of the electrons just before they reach the screen. Your final answer should have units of eV.
??=9.11×10^−31??
c = 3.0x10^8 m/s
h = 6.63x10^-34 js
The deBroglie wavelength of an object of momentum p is
Using p=mev
The kinetic energy is
To convert it to eV we divide the energy in joules by e
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