Question

What is the total energy (Joules) of the segment? [Round to nearest tenth: XX.X]

Mass = 5 kg

Moment of inertia = 0.12 kg-m2

Horizontal Velocity = 1.3 m/s

Vertical Velocity = 4 m/s

Angular Velocity = 8 rad/s

COM Height = 0.75 m

Answer 1

given

Mass, m= 5 kg

Moment of inertia, I = 0.12 kg-m2

Horizontal Velocity, vx = 1.3 m/s

Vertical Velocity, vy = 4 m/s

Angular Velocity, w = 8 rad/s

COM Height, h = 0.75 m

v = sqrt(vx^2 + vy^2)

= sqrt(1.3^2 + 4^2)

= 4.206 m/s

Total energy = potential energy + linear kinetic energy + rotational kinetic energy

= m*g*h + (1/2)*m*v^2 + (1/2)*I*w^2

= 5*9.8*0.75 + (1/2)*5*4.206^2 + (1/2)*0.12*8^2

= 84.8 J <<<<<<<<<<----------------Answer