Question

Calculate the change in entropy as 0.4091 kg of ice at 273.15 K melts. The latent heat of fusion of water is 333000 J/kg .

Answer 1

ans)

from above data that

we know that formula

Entropy Change = (Energy transferred) / (Temperature in kelvin)

that means that

deltaS = Q / T

here

Q = (mass)(latent heat of fusion)

Q = m(hfusion)

given that

m=0.4091 kg=409.1 g, h fusion =333J/g

substitue in above equation

Q = (409.1g)(333J/g)

Q= 136230.3 J

T(K) = T(C) + 273.15 = 273.15K

we know that

deltaS = Q / T

Q= 136230.3 J

deltaS = 136230.3J / 273.15K

deltaS = 498J/K

so the answer is  498J/K