Question

- Measuring Magnetic Fields] The horizontal component of the
Earth’s magnetic field is 2 x 10
^{-5}Tesla. Suppose you bring a bar magnet such that it is 3 cm from a magnetic compass. The bar magnet makes the compass deflect 15.6 degrees. What is the strength of the magnetic field due to the bar magnet at that location? Suppose this bar magnet is a magnetic dipole. What is the value of the magnetic dipole moment? Remember that

Answer #1

Using Earth's horizontal magnetic field formula ,magentic field due to bar magnet is calculated.

Using formula of horizontal magnetic field in terms of magnetic dipole moment , magnetic dipole moment is calculated.

At a point on the Earth’s surface the magnetic field has a
horizontal component due north of 1.8 ́ 10-5 T and a vertical
component downwards of 5.5 ́ 10-5 T.
(i) Draw a diagram.
(ii) Calculate the force on a 1.5 m length of wire carrying a
current of 13 A when the wire is held vertically with the current
flowing downwards.
(iii) Calculate the force when the wire is horizontal with the
current flowing west to east.

At the equator, the earth’s field is essentially horizontal;
near the north pole, it is nearly vertical. In between, the angle
varies. As you move farther north, the dip angle, the angle of the
earth’s field below horizontal, steadily increases. Green turtles
seem to use this dip angle to determine their latitude. Suppose you
are a researcher wanting to test this idea. You have gathered green
turtle hatchlings from a beach where the magnetic field strength is
50 μTμT and...

Lab Scenario:
You don't have a current meter in your underequipped lab.
So you make one out of a compass.
The wire you want to measure the current in is aligned with the
North South line.
You place your compass directly under the wire at a distance of
10cm from the wire.
With no current flowing, the compass needle points due
north.
When you turn on the current, the compass needle points 5
degrees west of north.
You now have...

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