Consider a cathode ray tube.
In this tube, a potential difference of ΔV = 111 V accelerates electrons horizontally in an electron gun. Positively charged anodes focus the electrons into a beam. Horizontal and vertical deflecting plates use potential differences to steer the beam.
In the main part of the cathode ray tube, there is a magnetic field with magnitude B = 3.40·10^-4 T. The direction of the magnetic field is upward and perpendicular to the initial velocity of the electrons.
What is the magnitude of the acceleration of the electrons?
Solution :
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