A person with a mass of 76 kg and a volume of 0.094 m3 floats quietly in water.What is the volume of the person that is above water?If an upward force F is applied to the person by a friend, the volume of the person above water increases by 0.0015 m3 . Find the force F.
Given data:
M = 76 kg
V = 0.094 m3
vb = 0.0015 m3
(a)
Fg = m*g
Fg = 76*9.81
Fg = 745.56 N
The buoyancy force is acting upward
Fb = (volume of the person below the water)*(weight of water)
Fb = (total volume - volume above water)*(weight of water)
Fb = (0.094 m3 - va)*(1000 kg/m3* 9.81)
Fb = 922.14 – 9810*va
Fb = Fg
922.14 – 9810*va = 745.56
va = 0.018 m3
(b)
Fg = Fb + FFriend
745.56 = (V – (va+vb))*(1000kg/m3*9.81) + FFriend
745.56 = [0.094 - (0.018 + 0.0015)]*(1000 kg/m3* 9.81) + FFriend
745.56 – 730.845 = FFriend
Friend = 14.7 N
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