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Three forces acting on an object are given by F1 = (−1.55î + 7.15ĵ) N, F2...

Three forces acting on an object are given by F1 = (−1.55î + 7.15ĵ) N, F2 = (5.10î − 1.4ĵ) N, and F3 = (−43.5î) N. The object experiences an acceleration of magnitude 3.55 m/s2.
a. What is the direction of the acceleration? (Counterclockwise from the x-axis)
b. What is the mass of the object? (kg)
c. If the object is initially at rest, what is its speed after 17.0 s?
d. What are the velocity components of the object after 17.0 s? (Let the velocity be denoted by v.) (v=____ i + ____ j) m/s

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Answer #1

The direction of acceleration is same as the direction of force. Divide the force magnitude by acceleration magnitude to find the required mass of the object. Use the equation of kinematics in vector form to find the velocity vector after the given time as shown below

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