Question

Your teacher tosses a basketball. The ball gets through the hoop (lucky shot). b ℓ 2.644 m 3.048 m 18 m/s 57 ◦ b b b b b b b b b b b b b b b b b b b b Figure: Not drawn to scale. How long does it take the ball to reach its maximum height? Answer in units of s. 005 (part 2 of 3) 10.0 points How long does it take the ball to reach the hoop? Answer in units of s

Answer 1

Part1)
Vo = 18 m/s at 72° from horizontal
Voy = initial vertical component of velocity = 18(sin 72°) = 17.12 m/s
Vox = initial horizontal component of velocity = 18(cos 72°) = 5.56 m/s
time to reach max height = Voy/g = 17.1/9.8 = 1.75 s (ANS 1)
Part 2)
time for ball to reach hoop = T = 1.75 + t
time for ball to fall from max height to basket height = t
t = √2H/g = √2(17.10-3.048)/g = √28.104/9.81 = √2.86= 1.69 s <== see note below
T = 1.75 + 1.69 ≈ 3.44 s (ANS 2)