Question

Calculate the centripetal force exerted on a 900kg car that rounds a 600m radius curve on horizontal ground at 25.0m/s. 2. Static friction prevents the car from slipping. Find the magnitude of the frictional force between the tires and the road that allows the car to round the curve without sliding off in a straight line.

A. 37.5N, Force of friction is the same as the centripetal force.

B. 864N, Force of friction is the same as the centripetal force

C. 938N*, F*, force of friction, is the same as the
centripetal force

D. 21,600N, Force of friction is the same as the centripetal force

Answer #1

mass = m = 900 kg

speed = v = 25 m/sec

radius = r = 600 m

centripetal force = F = m v^2 / r

F = 900 * 25^2 / 600

**F = 938 N**

static friction is prevent the car from slipping. hence frictional force = centripetal force

**so 938N , F, force of friction, is the same as
the centripetal force**

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