Question

6. Ice at 0 0C is used to cool water from room temperature (20 0C) to 0 0C. How much water can be cooled by 1 kg of ice?

Answer 1

Heat lost by ice when 0 oC ice is converted to 0 oC water,
Qi = m * Lf
Where m is the mass of ice and Lf is the latent heat of fusion.
Qi = 1 * 333.6 kJ
= 333.6 kJ

Heat gained by M kg of water, Qw = M * C * T
Where C is the specific heat of water, T is the temperature change.
Qw = M * 4.184 * (20 - 0)
= 83.68 * M kJ

Heat lost by ice = Heat gained by the water
Qi = Qw
333.6 = 83.68 * M
M = 333.6/83.68
= 3.987 kg