An air gun with a 30-cm long barrel fires a 56-g ball straight upwards. While the ball is in the barrel, compressed air exerts a constant force of 3.2-N force upwards. Calculate the maximum height above the end of the air gun that the ball reaches. Ignore any air resistance. [The pressure from the air gun is not air resistance]
Notes
• Solve this problem using Work and Energy. NO KINEMATICS ALLOWED!!!
• The ball travels 1.45 m above the end of the gun
. • This problem will require forces. Draw free-body diagrams for the ball
Suppose 'h' is the maximum height attained by the ball after firing.
So, potential energy gained by the ball, PE = m*g*h
Magnitude of the force, F = 3.2 N
Distpalcement, d = 30 cm = 0.30 m
Hence, work done by the force, W = F*d = 3.2 * 0.30 J
Apply work - energy theorem -
Work done = Potential energy gained by the ball
=> 3.2 * 0.30 J = m*g*h
=> 3.2 * 0.30 J = 0.056*9.8*h
=> h = (3.2 * 0.30) / (0.056*9.8) = 1.75 m
Hence, maximum height of the ball from the end of the gum = 1.75 - Length of the barrel
= 1.75 - 0.30 = 1.45 m (Answer)
Drwa the free-body diagram just considering the weight 'mg' acting in the downward direction.
Force, F acts in upward direction upto a distance 'd'.
Hope, you understand the solution!
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