Objects with masses of 285 kg and a 585 kg are separated by 0.480 m. (a) Find the net gravitational force exerted by these objects on a 68.0-kg object placed midway between them. magnitude N direction Correct: Your answer is correct. (b) At what position (other than infinitely remote ones) can the 68.0-kg object be placed so as to experience a net force of zero? m from the 585-kg mass
gravitational force is always attractive so the point will be somewhere in the middle of two
suppose to experience a net force of zero we place this mass at x distance away from 285kg so its distance from another mass (585 kg) is (0.48-x) m
now calculate total force on this and make it zero
Fnet = G*285*68 /x^2 - G*585*68 /( 0.48-x)^2 = 0
solve this for x= 0.197312 m
so its distance from 585 mass = 0.45-0.197312 = 0.252688 m answer
let me know in a comment if there is any problem or doubts
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