A 1.08 kg mass is at the center of a uniform spherical shell of mass 1.05*10^20 kg and radius 1.06*10^6 m.
(A)Find the resultant gravitational force on the mass.
b) Find the resultant gravitational force on the mass if it is placed just outside the shell.
magnitude =
direction =
(c) Find the value of g just outside the shell.
A) spherical shell gravitational field at the center ( r<R ) = 0
so force on the 1.08 kg mass will be zero
B) spherical shell gravitational field at out side ( r> ,=R)
Eg = GM/r^2
at surface r = R so Eg= G*M/R^2
so force on 1.08 kg mass = m* Eg like ( q*E)
F =1.08* 6.67*10^-11 *1.05*10^20 / ( 1.06*10^6)^2
magnitude =0.0067317 N
direction = towards center of spherical shell
C) value of g = 6.67*10^-11 *1.05*10^20 / ( 1.06*10^6)^2
=0.00623309 m/s^2
let me know in comment if there is any problem or doubt
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