Question

Derive the atomic packing fractions for the diamond structure and for the monatomic fcc lattice. For...

Derive the atomic packing fractions for the diamond structure and for the monatomic fcc lattice. For the fcc lattice, determine which real-space planes have the highest density of atoms.

Homework Answers

Answer #1
  • It is formed by carbon atoms.
  • Every carbon atom is surrounded by four other carbon atoms

    situated at the corners of regular tetrahedral by the covalent

    linkages.

  • The diamond cubic structure is a combination of two

     interpenetrating FCC sub lattices displaced along the body

    diagonal of the cubic cell by 1/4th length of that diagonal.

  • Thus the origins of two FCC sub lattices lie at (0, 0, 0) and

    (1/4, 1/4,1/4)

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Calculate the atomic packing factor (APF) for the FCC lattice and find the theoretical density of...
Calculate the atomic packing factor (APF) for the FCC lattice and find the theoretical density of FCC Ni (A=58.7g/mole, atomic radius:0.1246 nm).
Calculate the structure factor for monoatomic crystals in FCC and diamond lattice symmetries. Discuss the extinction...
Calculate the structure factor for monoatomic crystals in FCC and diamond lattice symmetries. Discuss the extinction rules for diffraction spots parametrized by the reciprocal lattice indices (h, k.l). Compare the differencies in the rules for the two crystals. What is the connection of the result to the lattice planes?
What is the relation between atomic radius r and lattice constant a in the case of...
What is the relation between atomic radius r and lattice constant a in the case of face- centered cubic (FCC) structure? State the number of atoms in a unit cell for FCC structure and hence deduce the atomic packing factor.
A certain material has a FCC crystal structure with an atomic radius of 1.44 A° (1...
A certain material has a FCC crystal structure with an atomic radius of 1.44 A° (1 A° = 10-8 cm), and an atomic mass of 197. Calculate: a) The lattice constant ‘a’ of unit cell in cm, b) The atomic packing factor of the material.
Show if lead is an FCC or a BCC crystal structure. Lead (Pb) has an atomic...
Show if lead is an FCC or a BCC crystal structure. Lead (Pb) has an atomic radius of 0.175 nm and a density of 11.35 g/cm3 . Use this information to determine whether it has an FCC or a BCC crystal structure. Please also provide the correct units.
1) For a metal that has the face-centered cubic (FCC) crystal structure, calculate the atomic radius...
1) For a metal that has the face-centered cubic (FCC) crystal structure, calculate the atomic radius if the metal has a density of (8.000x10^0) g/cm3 and an atomic weight of (5.80x10^1) g/mol.  Express your answer in nm. 2) Consider a copper-aluminum solid solution containing (7.82x10^1) at% Al. How many atoms per cubic centimeter (atoms/cm^3) of copper are there in this solution? Take the density of copper to be 8.94 g/cm3 and the density of aluminum to be 2.71 g/cm3.
Lead has a fcc lattice of constant a = 0.494 nm. The Young's modulus of elasticity...
Lead has a fcc lattice of constant a = 0.494 nm. The Young's modulus of elasticity for lead is EY = 1.6 · 1010 Nm− 2. If lead melts when the average amplitude of atomic vibrations is 15.8% of the distance between atoms (Lindemann criterion), calculate: (a) The distance of adjacent atoms in the fcc lattice. (b) Calculate the Debye temperature θD for lead if the phase velocity „c“ of phonon propagation for longitudinal and transverse modes in the fcc...
In a material with a cubic structure let density be 0.855 mg/m3, atomic mass=39.09 gr /...
In a material with a cubic structure let density be 0.855 mg/m3, atomic mass=39.09 gr / mol and lattice parameter =5.344 Angstrom. Based on this data, determine the type of Lattice and find the number of atoms in the Lattice.
Iron (Fe) crystallizes in a body-centered cubic structure with a lattice constant of 0.287 nm: Use...
Iron (Fe) crystallizes in a body-centered cubic structure with a lattice constant of 0.287 nm: Use drawing to show how the iron atoms are packed in the unit cell. How many iron atoms are contained in each unit cell?         Use drawings to show how the iron atoms are arranged on the (100) and (110) planes.                    Determine the density of iron (g/cm3) by dividing the total mass of iron atoms in the unit cell by the volume of the unit cell....
Iron (Fe) crystallizes in a body-centered cubic structure with a lattice constant of 0.287 nm: a....
Iron (Fe) crystallizes in a body-centered cubic structure with a lattice constant of 0.287 nm: a. Use drawing to show how the iron atoms are packed in the unit cell. How many iron atoms are contained in each unit cell?         b. Use drawings to show how the iron atoms are arranged on the (100) and (110) planes.        c. Determine diameter of iron atom    d. Determine the density of iron (g/cm3) by dividing the total mass of iron atoms in...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT