Question

A black mass m and velocity v slides horizontally on a surface a distance d. What is m (mue)

Answer 1

Suppose acceleration of the mass = a

Use the expression -

v2^2 = v1^2 + 2*a*d

Given that -

Initial velocity, v1 = v

Final velocity, v2 = 0 (After stop)

Distance = d

a = ?

Put the values -

0 = v^2 + 2*a*d

=> a = -v^2 / (2*d)

So, the magnitude of the acceleration, a = v^2 / (2*d) -------------------------------------(i)

Now, suppose coefficient of friction =

So we have the relation -

a = *g

Put the value of the acceleration from (i) -

*g = v^2 / (2*d)

=> = v^2 / (2*d*g) (Answer)

Hope, you understand the solution!