Question

A 23 g ball of clay traveling east at 4.0 m/s collides with a 40 g...

A 23 g ball of clay traveling east at 4.0 m/s collides with a 40 g ball of clay traveling north at 2.3 m/s . a) What is the movement direction of the resulting 63 g blob of clay? b)What is the speed of the resulting 63 g blob of clay?

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Answer #1

Mass of Ball A,mA =23g

Initial velocity of ball A =, vA = 4m/s towards east

Mass of Ball B,mB =40g

Initial velocity of ball B =, vB = 2.3m/s towards north

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Momentum is conserved

---------------------------------

Consider Conservation of Momentum in x direction (towards East)

Momentum Before Collision in x direction =Momentum After Collision in x direction

---------------(1)

----------------------------------

Consider Conservation of Momentum in y direction (towards North)

Momentum Before Collision in y direction =Momentum After Collision in y direction

---------------(2)

------------------------------

Divide Equation (2) by (1)

(a)ANSWER:

=================

(b)From Equation (1)

ANSWER:

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