Question

Find the mass of water that vaporizes when 3.04 kg of mercury at 201 °C is added to 0.192 kg of water at 83.0 °C.

Answer 1

Water vaporizes at the temperature t = 100 degree celcius. So, from the calorimetric equilibrium, we have the condition that
   
   the heat received by water = heat lost by the mercury
And mathematically
  
   
where, L_w is the latent heat of water to vaporize and M is the mass of the water that will vaporize.
So,
  
  
so, given the values,


  we get