Find the mass of water that vaporizes when 3.04 kg of mercury at 201 °C is added to 0.192 kg of water at 83.0 °C.
Water vaporizes at the temperature t = 100 degree celcius. So,
from the calorimetric equilibrium, we have the condition that
the heat received by water = heat lost by the
mercury
And mathematically
where, L_w is the latent heat of water to vaporize and M is the
mass of the water that will vaporize.
So,
so, given the values,
we get
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