Question

Find the mass of water that vaporizes when 3.04 kg of mercury at 201 °C is...

Find the mass of water that vaporizes when 3.04 kg of mercury at 201 °C is added to 0.192 kg of water at 83.0 °C.

Homework Answers

Answer #1

Water vaporizes at the temperature t = 100 degree celcius. So, from the calorimetric equilibrium, we have the condition that
   
   the heat received by water = heat lost by the mercury
And mathematically
  
   
where, L_w is the latent heat of water to vaporize and M is the mass of the water that will vaporize.
So,
  
  
so, given the values,


  we get
  

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Find the mass of water that vaporizes when 3.78 kg of mercury at 248 °C is...
Find the mass of water that vaporizes when 3.78 kg of mercury at 248 °C is added to 0.260 kg of water at 97.2 °C.
Find the mass of water that vaporizes when 3.28 kg of mercury at 227 °C is...
Find the mass of water that vaporizes when 3.28 kg of mercury at 227 °C is added to 0.233 kg of water at 93.6 °C.
A copper pot with a mass of 0.480 kg contains 0.170 kg of water, and both...
A copper pot with a mass of 0.480 kg contains 0.170 kg of water, and both are at a temperature of 20.0 ?C . A 0.270 kg block of iron at 83.0 ?C is dropped into the pot. Find the final temperature of the system, assuming no heat loss to the surroundings.
Calculate the change in entropy of the surroundings when 1.0 mol of water vaporizes as 1000C....
Calculate the change in entropy of the surroundings when 1.0 mol of water vaporizes as 1000C. The heat of vaporization of water is 40.6 kj/mol
A Styrofoam bucket of negligible mass contains 1.90 kg of water and 0.460 kg of ice....
A Styrofoam bucket of negligible mass contains 1.90 kg of water and 0.460 kg of ice. More ice, from a refrigerator at -16.0 ∘C, is added to the mixture in the bucket, and when thermal equilibrium has been reached, the total mass of ice in the bucket is 0.788 kg . Assuming no heat exchange with the surroundings, what mass of ice was added? (kg)
A Styrofoam bucket of negligible mass contains 1.55 kg of water and 0.475 kg of ice....
A Styrofoam bucket of negligible mass contains 1.55 kg of water and 0.475 kg of ice. More ice, from a refrigerator at -15.4 ∘C, is added to the mixture in the bucket, and when thermal equilibrium has been reached, the total mass of ice in the bucket is 0.784 kg . Assuming no heat exchange with the surroundings, what mass of ice was added?
A Styrofoam bucket of negligible mass contains 1.55 kg of water and 0.475 kg of ice....
A Styrofoam bucket of negligible mass contains 1.55 kg of water and 0.475 kg of ice. More ice, from a refrigerator at -15.4 ∘C, is added to the mixture in the bucket, and when thermal equilibrium has been reached, the total mass of ice in the bucket is 0.784 kg . Assuming no heat exchange with the surroundings, what mass of ice was added?
A perfectly insulated thermos contains 0.300 kg of water initially at 50 degrees C. A mass...
A perfectly insulated thermos contains 0.300 kg of water initially at 50 degrees C. A mass os of 0.100 kg of water initially at 10 degrees C is added. Ignore any heat exchanges with the outside environment. Take the specific heat capacity of liquid water as 4190 J/kgK. A) Draw a diagram for the situation, indicating the relative masses and temperatures. B) Find the final temperature of the combined water after they have mixed and attained thermal equilibrium (HINT: equate...
The specific heat of mercury is 138 J/kg°C. Determine the latent heat of fusion of mercury...
The specific heat of mercury is 138 J/kg°C. Determine the latent heat of fusion of mercury using the following calorimeter data: 1.30 kg of solid Hg at its melting point of -39.0°C is placed in a 0.620 kg aluminum calorimeter with 0.400 kg of water at 12.80°C; the resulting equilibrium temperature is 2.91°C
When 1 kg of salt is added to a solution of salt and water, the solution...
When 1 kg of salt is added to a solution of salt and water, the solution becomes 33 1/3 % salt by mass. When 1 kg of water is added to the new solution, the resulting solution is 30% by mass. The percentage of salt in the original solution is:
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT