Question

A projectile is fired from the origin (at y = 0 m) as shown in the figure. The initial velocity components are V0x = 400 m/s and V0y = 82 m/s. The projectile reaches maximum height at point P, then it falls and strikes the ground at point Q. In the figure, the y-component of the velocity of the shell of point P is closest to:

-80 m/s

zero

-160 m/s

+80 m/s

+160 m/s

Answer 1

In Projectile motion there is no acceleration in horizontal direction so the value V₀x =400m/s remains same until the projectile strikes ground.

But,in Vertical direction acceleration due to gravity acts downwards ,so V₀y =82m/s starts decreasing

and when projectile attains maximum Height ,Vy becomes ZERO ,and the velocity in y direction starts increasing while falling down.

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ANSWER: Here P is given as Maximum Height ,so y component of velocity will be ZERO at that point P

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