solve for q given that
k = 8.99 x10^9
slope = 2.43030418
q1 and q2 are equivalent to eachother
q is the charge
the formula is
slope=k(q^2)
im just not confident about the units
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you must have plotted graph for coloumb force
because q1 and q2 are equivalent
so
so slope for this graph between F and 1/r2 is
=kq^2
because unit of force is Newton and of distance= meter
so unit of slope = Nm2
and of Charge is Coloumb
so
so we have given
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