Question

Question 1)

a. Describe qualitatively but specifically how the circuit quantities change after the switch is closed in the circuit a) current b) voltage across the capicitor. Explain why these quantities change as they do, in terms of motion and presence of the capacitor.

b. Imagine repeating the timing experiments you can in this lab, only this time starting with a partially-charged capacitor. Describe how the timings differ from above, explaining how this difference originated from specific electrical quantities in the circuit (e.g. charge, voltage, etc. )

*please explain clearly! Thank You!!! (Do not have a figure)

Answer 1

As we know, V = I * R

I represents current. Unit of current is Amps

R is a resistance. Unit of resistance is ohms

V is a voltage of a battery we are using in a circuit

if we increase the voltage, ultimately current will increase while the resistance will remain the same in the circuit.

When the circuit is open the charged particles are prevented from passing through

These charged particles spread throughout the wire and the number of charged particles passed by each second we refer it as current

C = Q/V charge divided by the voltage

where the charge is a variable and voltage is a variable but the capacitance is constant

Q = C*V

current is a change in a voltage in a per unit time.