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A 10 g hoop has a radius of 15 cm. A force vector of F =...

A 10 g hoop has a radius of 15 cm. A force vector of F = 10i -30j mN   acts on the wheel at position vector r = 15i cm . What is the magnitude of the angular acceleration of the wheel?

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Answer #1

Force vector is

The position vector is

Torque on the hoop is

Magnitude of torque is

Mass of hoop is M=10g=0.010kg

Radius of the hoop is R=15cm=0.15m

Moment of inertia of the hoop is

The angular acceleration produced by the torque is

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