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I have 10 bags of coins containing 10 coins each. All the coins in the bags...

I have 10 bags of coins containing 10 coins each. All the coins in the bags are identical in appearance and mass (10.0 g each) except for the coins in one bag. In that bag the coins are more massive than the average coin by 0.1 g. If you are allowed only one weighing using a digital scale, how would you determine which bag contained the more massive coin? Hint: You may remove the coins from the bags.

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Answer #1

Take one coin from first bag , 2 coins from second bag , three coins from third bag and.......... 10 coins from 10th bag . If they all had same weight then the total would have been 10+20+30+40+50+60+70+80+90+100=550 . BUT ONE of the bag is not correct . If it was first bag then total will be 550.1gm

If it was second bag then weight will be 550.2 gm

Similarly third bag then weight will be 550.3 gms and so on . Seeing the weight above the amount 550 . We know which bag it is

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