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Let's say you completely boil 3.96 kg of rubbing alcohol at constant air pressure 99.7 kPa....

Let's say you completely boil 3.96 kg of rubbing alcohol at constant air pressure 99.7 kPa. What will be the resulting volume of vapor, in m3, assuming it behaves like an ideal gas? (Possibly useful: density of rubbing alcohol: 0.786 kg/liter, molar mass of rubbing alcohol: 60.1 kg/kmol, gas constant R = 8.314 kJ K−1 kmol−1. Beware K vs °C, Pa vs kPa, g vs kg, mol vs kmol, etc.)

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