Question

A physics book slides off a horizontal table top with a speed of 1.15 m/s. It strikes the floor in 0.500 s. Ignore air resistance. (Assume the book's horizontal direction and upward are positive.)

(a) Find the height of the table top above the floor.
m

(b) Find the horizontal distance from the edge of the table to the point where the book strikes the floor.
m

(c) Find the horizontal and vertical components of the book's velocity just before it reaches the floor.
m/s (horizontal component)
m/s (vertical component)

Find the magnitude and direction of the book's velocity just before it reaches the floor.
m/s
° (below the horizontal)

Answer 1

Initial horizontal velocity = 1.15 m/s

time= 0.5 seconds

a) As there is no initial vertical velocity,

we can use kinematic equation, to calculate the height

h = 0.5gt^2

h = 0.5(9.80) ( 0.5)² = 1.225 m approx.( height of table top)

b) horizontal distance = speed x time= 1.15 (0.5)= 0.575 m approx.

c) Vx ( horizo ntal componenT ) = 1.15 m/s ( as there is no accelertaion involved, it won't change)

d) Vy = 9.8( 0.5)= 4.9 m/s approx.

e) magnitude of velocity = - sqrt( Vx^2 + Vy^2 )= sqrt( 1.15^2 + 4.9^2) = 5.033 m/s approx.

f) tanθ = Vy/Vx= 4.9/ 1.15 = 76.79 degree below horizontal

Please rate my answer, good luck...