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Coulomb's law for the magnitude of the force F between two particles with charges Q and...

Coulomb's law for the magnitude of the force F between two particles with charges Q and Q′separated by a distance d is

|F|= (K) |QQ′| / d2

where K=1 / 4πϵ0, and ϵ0=8.854×10−12  C2 / (N⋅m2) is the permittivity of free space.

Consider two point charges located on the x axis: one charge, q1 = -13.5 nC , is located at x1 = -1.745 m ; the second charge, q2 = 31.5 nC ,is at the origin (x=0.0000).

What is the net force exerted by these two charges on a third charge q3 = 47.5 nCplaced between q1 and q2 at x3 = -1.200 m ?

Your answer may be positive or negative, depending on the direction of the force.

Express your answer numerically in newtons to three significant figures.

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